Question

galvanometer has current range 20mA and voltage range of 600mV to convert this galvanometer into ammeter of range 10A shunt resistance required is

Answer 1

Explanation:

Given : V=750×10−3V;

Ig=15×10−3A and I=25A

Using, a=Igy

=15×10−3750×10−3=50Ω

Ig=S+aS×I

15×10−3=(S+50S)×25

∴S=0.03Ω

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