gamma=10^8.breaking strain =0.2%.what should be the minimum cross section to support 10kg mass
Answers
Answered by
0
Answer:
Explanation:
=
breakingstrain
A
L
⇒ A=
r×B.S
L
=
7×10
9
×(
1000
2
)
10
4
A=7.1×10
Answered by
0
Answer:SORRY I DONT KNOW ANSWER FOR THIS QUESTION
Explanation:
Similar questions