Math, asked by kingfahad1395, 11 months ago

Gangamma was selling a kerosene funnel in her shop which is made aluminium sheet which is a combination of frustum and cylinder

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Answered by sowmyalathahkhonnava
9

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Answered by AditiHegde
0

Gangamma was selling a kerosene funnel in her shop which is made aluminium sheet which is a combination of frustum and cylinder.

Area of aluminium sheet is 782 4/7 cm^2

  • Area of aluminium sheet is given by,
  • CSA of cylinder + CSA of frustum of cone
  • = 2πrh + π (r1+r2)l
  • = 2πrh + π (r1+r2)√[h^2 + (r1-r2)^2]
  • = 2π × 8/2 × 10 + π × (18/2 + 8/2) × √[(22-10)^2 + (18/2 - 8/2)^2]
  • = 80 π + π (26/2) √ (144 + 25)
  • = 80 π + π (13) √ (169)
  • = 80 π + π (13) × 13
  • = 80 π + 169 π
  • = 249 π
  • = 249 × 22/7
  • = 782 4/7 cm^2
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