Question

gap between Bohr's atomic radii of he +ve of 3rd orbit and 5 orbit will be.​

Answer 1

Heya,

Bohr's orbit for a orbit n of element having atomic number z is given by :- ( in angstrom)

$\frac{0.529 {n}^{2} }{z}$

For He, z = 2,

for n = 3

$\frac{.529 \times 9}{2} \\ \\ for \: n = 5 \\ \\ \frac{.529 \times 25}{2} \\ \\ hence \: gap = \frac{0.529( \frac{25}{2} - \frac{9}{2}) }{} \\ \\ = 0.529 \times 8 \\ = 4.232 \: angstrom$

Regards

Kshitij