Question

Gap between two electrodes of spark up test used in automobile engine is 1.25mm. If potential of 20V is applied across the gap, what will be the magnitude of electric field between the electrodes?​

Answer 1

Electric field between the gap will be equal to 16000 N/C

Explanation:

We have given gap between two electrodes of spark = 1.25 mm

We know that 1 m = 1000 mm

So d= $1.25mm=1.25\times 10^{-3}m$

Potential applied in the gap = 20 volt

We have to find the electric field between the gap

Potential in the gap will be equal to $V=Ed$, here E is electric field and d is distance

So $20=E\times 1.25\times 10^{-3}$

E = 16000 N/C

So electric field between the gap will be equal to 16000 N/C

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