Question

Gap between two electrodes of the spark up is used in automobile engine 1.25 mm the potential of 20 is applied across the gas what will be the magnitude of electric field between the electrodes

Answer 1

The magnitude of electric field between the electrodes will be 16000 V/m.

Explanation:

Given data:  

ΔV =  20 V

x = 1.25 mm = 1.25 × 10∧-3 m

We know that:

E = - ΔV/  Δx

• Where  ΔV = Potential difference
• Δx = gap between electrodes
• E = Electric field.

So, E = 20/(1.25 × 10^-3)  

E = 16000 V/m

Hence the magnitude of electric field between the electrodes will be 16000 V/m.

Also learn more

An electron moving with a velocity of 5×10^4 m/s enters into a uniform electric field and acquires a uniform acceleration of 10^4 m/s^2 in the direction of its initial motion

1. Calculate the time in which the electron would acquire a velocity double of its initial velocity and

2) how much distance the electron would cover in this time?

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