Question

Gap between two electrodes of the spark up is used in automobile engine 1.25 mm the potential of 20 is applied across the gas what will be the magnitude of electric field between the electrodes

Answer 1

The magnitude of electric field between the electrodes will be 16000 V/m.

• We know that,

        E = - ΔV/  Δx

• Where  ΔV = Potential difference,  Δx = gap between electrodes, E = Electric field.

• Given,  

       ΔV =  20 V

       x = 1.25 mm = 1.25 × 10∧-3 m

• So, E = 20/(1.25 × 10∧-3)  = 16000 V/m.

Answer 2

Explanation:

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