Math, asked by cpistol61, 4 months ago

gary sold 8 more tickets than peter. tracy sold 12 less than peter. they sold 50 tickets in total. how many tickets did gray sell.​

Answers

Answered by bhavisr
3

\huge{\underline{\mathtt{\red{❥EX}\pink{P}\green{L}\blue{AT}\purple{I}\orange{ON}}}}

Assuming,

Peter sold tickets = x ( Because both the Gary and tracy tickets are according to Peter)

Gary = x + 8 ( Sold 8 more ticket than Peter, given)

Tracy = x - 12 ( Sold 12 less ticket than Peter, given)

Total tickets sold = 50

So Peter + Gary + Tracy = 50

Therefore,

x + x +8 + x -12 = 50

3x - 4 = 50

3x = 54

x = 18

Therefore,

Peter sold x Tickets = 18

Garry sold 8 More than Peter (x + 8) = 26

Tracy sold 12 less than Peter (x - 12) = 6

So, Total tickets sold = 18 (Peter) + 26 (Garry) + 6 Tracy = 50 Tickets.

So Gary (Gray) sold 26 Tickets.

\huge{\underline{\mathtt{\red{❥HO}\pink{PE}\green{IT'S}\blue{HE}\purple{LP}\orange{FUL}}}}

\huge\underline\mathbb{\red F\pink {O}\purple {L} \blue {LO} \orange {W}\green {ME}}

\huge{\underline{\pink{Thanks:)❤}}}

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