gas A is 16 times denser than gas B 100cm3 of gas A diffuses through a hole in 20 seconds. Calculate the volume of B that will diffuse through the hole in 30 seconds
Answers
Hi,
Answer:
The volume of B that will diffuse through the hole in 30 s is 600 cm³.
Explanation:
Given Data:
Gas A is 16 times denser than Gas B
The volume of gas A, Va = 100 cm³
Time taken by gas A to diffuse through a hole, ta = 20 s
Time taken by gas B to diffuse through a hole, tb = 30 s
To find: volume of gas B, Vb
Let
the molecular mass of gas A be “Ma”
the molecular mass of gas B be “Mb”
rate of diffusion of gas A be “Ra”
rate of diffusion of gas B be “Rb”
Since when the density of a gas increases with increase in the molecular masses of the gas. Therefore, according to the given data of the question above we can say
Ma = 16 * Mb …. (i)
Also, rate of diffusion = volume / time = V/t
We know that the gas A is given to be 16 times denser than gas B, therefore, the rate of diffusion of gas B will be √16 = 4 times faster than that of gas A.
By using Graham’s law of diffusion, we have
Ra/Rb = √[Mb/Ma]
∴ [Va/ta] / [Vb/tb] = √[Mb/Ma]
Or, [100/20] / [Vb/30] = √[Mb/(16*Mb)]
Or, 5 / [Vb/30] = √[1/(16)]
Or, 30 * 5 / Vb = ¼
Or, Vb = 150 * 4 = 600 cm³
Hope this helps!!!!
Answer:
Explanation:
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