Question

gas at 30 degree celsius is heated at constant pressure till its volume is double find the final temperature of the gas​

Answer 1

Answer:

Explanation:

Applying following expression

P1 x V1 / T1 = P2 x V2 / T2

P1 = P2

Therefore T2 = V2 x T1 / V1

V2 = 2 x V1

T1 = 30 degree c = 303 K

T2 = 2 x 303 = 606 K

Answer 2

Given :

• A gas at 30° Celsius is heated at constant pressure till its volume is double.

To Find :

•The final temperature of the gas =?

Formula :

Charles Law :

$\red\bigstar\boxed{\bf{ \dfrac{V_{1} }{T_{1} } =\dfrac{V_{2} }{T_{2} } }}$

Given :

Values :

$\bullet\sf{V_{1}=V}$

$\bullet\sf{V_{2}=2V}$

$\bullet\sf{T_{1}=(273+30°)=(303 kelvin ) }$

$\bullet\sf{T_{2}=?}$

By using Charles Law :

$\implies\sf{\dfrac{V_{1} }{T_{1} }=\dfrac{V_{2} }{T_{2} } }$

Substituting the values :

$\\ \implies\sf{\dfrac{V}{303 } =\dfrac{2V}{T_{2} }}$

$\\ \implies\sf{\dfrac{\cancel{V} }{303} =\dfrac{2 \cancel{V} }{T_{2} } }$

$\\ \implies\sf{T_{2}= 2 \times 303 }$

$\\ \implies\sf{T_{2}=606 \: Kelvin }$

$\\ \implies\sf{T_{2}=606-273=303° Celsius }$

The final temperature is 303° Celsius.