gas at zero degree celsius is heated both its pressure and volume increases twice the initial find its final temperature
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This kind of problem can be solved using the combined gas laws. PV/T = k. Let T1 = initial temperature; T2 = the final temperature; V1 = the initial volume; V2 = the final volume; P1 = initial pressure and P2 = final pressure.
Given: T1 = 0 degrees Celsius = 273 K; P2 = 2P1; V2 = 2V1
(P1 * V1) / T1 = (P2 * V2) / T2 combined gas laws
(P1 * V1) / 273 = (2P1 * 2V1) / T2
Cancelling the common factors V1 and P1 we get
1 / 273 = 4 / T2
T2 = 273 * 4
T2 = 1092 K
T2 = 1092 – 273
T2 = 819 Celsius
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