Question

gas bulb contains air at 1 atm and 27oC.The maximam pressure which the bulb can withstand is 2 atm.Find the temperature at which it bursts.


1) 327 degree celcius

2) 600 K

3) 100 degree celcius

4) 0K



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Answer 1

Answer:

According to Gay Lussac's law, the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature, i.e.,

P∝T

∴

P

2

P

1

=

T

2

T

1

Let T be the temperature at which the bulb burst.

Here,

P

1

=1atm

P

2

=2atm

T

1

=27℃=(27+273)K=300K

T

2

=?

∴

2

1

=300T

⇒T=300×2=600K

Hence the temperature at which the bulb bursts is 600K.

Explanation:

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