Question

gas evolved at the cathod during electrolyis of water?​

Answer 1

Answer:

In pure water at the negatively charged cathode, a reduction reaction takes place, with electrons (e−) from the cathode being given to hydrogen cations to form hydrogen gas. The half reaction, balanced with acid, is: Reduction at cathode: 2 H+(aq) + 2e− → H2(g)

Answer 2

Explanation:

In pure water at the negatively charged cathode, a reduction reaction takes place, with electrons (e−) from the cathode being given to hydrogen cations to form hydrogen gas. The half reaction, balanced with acid, is: Reduction at cathode: 2 H+(aq) + 2e− → H2(g)

I HOPE THIS HELPS YOU