Question

gas expands in volume from 2L to 5L against a pressure of 1atm at constant temperature. The workdone by the gas will be​

Answer 1

Answer:

I don't know mein, I will be a problem with the new one, but the problem with this list of the following is the meaning utilise the, and the other hand

Answer 2

Answer:

-303.9J

Explanation:

Given,

The gas is expanding,

initial volume of gas = 2 L

final volume of gas = 5 L

change in volume v = final volume - initial volume

=5 L - 2 L

= 3 L

pressure = 1 atm

Since, the pressure is constant

Hence, work done = pressure x change in volume

= 1 atm x 3 L

= 3 L atm

Since, 1 L atm= 101.325 J

so, 3 L atm= 3 x 101.325 J

= 303.9 j

Since, the work done by the system so, the work done should be negative and the work done will be -303.9 J