Gas hydrogen is collected over water at 14°C, The pressure of hydrogen collected fond
to be 760 mm Hg, Calculate the pressure of dry hydrogen if water vapour precawe is
14 °C is 12 mm Hg.
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0
Answer:
45.58
Explanation:
Given that
P
1
=750mmHg−14mmHg=736mmHg
V
1
=50cm
3
,T
1
=17
0
C=290K
P
2
=760mmHg
V
2
=?cm
3
,T
2
=0
0
C=273K
Hence the Gas equation
T
1
P
1
V
1
=
T
2
P
2
V
2
290
736×50
=
273
760×V
2
∴V
2
=
290×760
736×50×273
V
2
=45.58 cm
3
Thus, the volume of dry gas at STP is 45.58 cm
3
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