Question

Gas in a balloon occupies 2.50L at 300.0K. At what temperature will the balloon expand to 7.50L?

Answer 1

Given:

Gas in a balloon occupies 2.50L at 300.0K.

To find:

The temperature is at 7.5 L volume.

Solution:

According to the ideal gas law, we know that PV=nRT

At constant composition and pressure, volume is proportional to T.

Thus we can write-

V1T2=V2T1

Where V1 is the initial volume=2.5L.

V2 is the final volume=7.5L.

T1 is the initial temperature =300K.

T2 is the final temperature =x K.

Thus we can write-

2.5×x=7.5×300

x=900

The temperature is 900K at which the balloon will expand to 7.5L.

Answer 2

Answer:

At 900K the gas will expand to 7.50l

Explanation:

According to Charle's law the volume of a gas is directly propotional to the temperature of a gas at constant pressure.

VT = constant

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$

$V_1 =$ Volume of gas at 300K = 2.50l

$T_1 =$ 300K

$V_2 =$ Volume after expansion = 7.50l

$T_2 = ?$

$\frac{V_1}{T_1} = \frac{V_2}{T_2} \\\frac{2.50}{300} = \frac{7.50}{T_2}\\\frac{7.50*300}{2.50} = T_2\\900K = T_2$

At 900K the gas will expand to 7.50l