Question

Gas is compressed slowly and isothermally at 300K from 1 bar to 8 bar. Calculate the work done using the given state of equation. (B = -5.397 X 10-6 m3 /mol) (note: volume at each stage should be near to the ideal gas volume)
/ = 1 + / ​

Answer 1

Answer:

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Answer 2

Given:

$P_1 = 1 bar$

$P_2 = 8 bar$

$Temperature = 300K$

To find:

Work done

Explanation:

The process is an isothermal and reversible process

∴ for an isothermal and reversible process:

work done $= - nRT ln\frac{P_1}{P_2}$

Considering n = 1 mole

Substituting $R = 8.314 J(mol/K)$

$W = - 1\times 8.314\times 300 ln\frac{1}{8}$

    $=5,185.4418 J$  $= 5.185 kJ$

As it can be seen from the pressure values that the gas is compressed ;

∴ work done $= 5.185 kJ$