Question

Gas is compressed slowly and isothermally at 300K from 1 bar to 8bar. Calculate the
work done using the given state of equation. (B = -5.397 X 10-6 m3
/mol)
(note: volume at each stage should be near to the ideal gas volume)

PV/RT = 1 +B/V

Answer 1

Answer:

hi i gave u thx

Explanation:

Answer 2

GIVEN :

n = 1 mole

$P_{1}$ = 1 bar

$P_{2}$ = 8 bar

T = 300 K

TO FIND : WORK DONE ?

By using the formula

Work done = -nRT ㏑$\frac{P_{1} }{P_{2} }$

= -1 x 8.314  x 300 x ㏑$\frac{1}{8}$

=5186.54J