Question

Gas mineture has following
composihan
(i) Partial Pressure of each component
Volun
me- 10% CH4 g 30%. Ethane and 60 % Hydrogen
and flows at rate of 1000 L/s at 303k and
2000 mm Hy gauge pressure, computer
ů Mole fraction of each component
(ii) Concentration of each component in moll)
(in) Average molecular weight. .... B marks​

Answer 1

According to Henry's law, the solubility of gas in a liquid is directly proportional to the pressure of the gas.

X=K  

h

​  

×P

X is the mole fraction of gas, K  

h

​  

 is the Henry's law constant and P is the partial pressure of the gas.

Also mole fraction of ethane will be directly proportional to its mass.

WP  

′

=W  

′

P

W is the mass of ethane in first solution and P is the partial pressure of ethane in first solution.

W  

′

 is the mass of ethane in second solution and P  

′

 is the partial pressure of ethane in second solution.

6.56×10  

−3

×P  

′

=5.00×10  

−2

×1

P  

′

=7.6

Hence, the partial pressure of gas will be 7.6 bar.