Gas samples A, B, C are contained at STP. Partial pressure of sample A is 38.0 kPa and sample B is 19.0 kPa. What is the partial pressure of sample C?
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Answer:
⇒PC=44.3kPa
Explanation:
If the mixture of gases A, B and C is contained at STP, this means that the total pressure is 1 atm.
Note that 1atm=101.325kPa
According to Dalton's law, the total pressure of a mixture is equal to the sum of the partial pressures of the gases in the mixture:
Ptotal=PA+PB+PC
⇒PC=Ptotal−PA−PB
⇒PC=101.325kPa−38.0kPa−19.0kPa=44.3kPa
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