Question

Gaurav on his moped travels 5 km at 20 km /h and next 5 km at 30 km/h. Calculate average speed. please give me full solution.​

Answer 1

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$average \: speeed \: \overline{V}\:= \frac{total \: distance}{total \:ti me} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{s_1 + s_2}{t_1 + t_2} \: \: - - - (1)\\ We\:know \:that\:,\\S\:=vt \\ Now\:first \: case \: : - \\ t_1 = \frac{s_1}{v_1} = \frac{5}{20} = \:\frac{1}{4}\: hours \\ \\ second \: case \: :- \\ t_2 = \frac{s_2}{v_2} = \frac{5}{30} = \:\frac{1}{6} \: hours$

Now,

$from \: eqn \: (1) \\ \overline V \: = \frac{5 + 5}{ \frac{1}{4} + \frac{1}{6} } \\ \: \: \: \: \: \: = 24 \: \: km {h}^{ - 1}$

Answer 2

Answer:

ans in attachment

Explanation:

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