Question

Gaurav sold his motorcycle to Vikas at a loss of 28%. Vikas spent 1680 Rs on its repairs and sold the motorcycle to Abhimanyu for 35910 Rs,thereby making a profit of 12.5%. Find the cost price of the motorcycle for Gaurav.​

Answer 1

Given :-

• Gaurav sold his motorcycle to Vikas at a loss of 28%.

• Vikas spent 1680 Rs on its repairs and sold the motorcycle to Abhimanyu for 35910 Rs,thereby making a profit of 12.5%.

To find:-

• The cost price of the motorcycle for Gaurav.

Solution:-

Let Cost price if bikes is Rs. x.

➪ Gaurav sold tbe bike at y = x - 28x/100 = 72x/100.

C.P for vikas = 72x/100 + 1680

We know :

★ Profit = S.P - C.P / C.P  × 100  

Therefore ,

➪ Profit = 12.5% [(35910) - (0.72x + 1680)] x 100 / (0.72x + 1680) = 12.5

 ⇒ (3423 - 0.72x) / (0.72x + 1680) = (125 / 100).

➪ C.P = 31920

⇒ 72x/100 = 30240

⇒ x = Rs.42000.

Hence, the cost price of motorcycle for gaurav is Rs.42000.

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Answer 2

Question:

Gaurav sold his motorcycle to Vikas at the loss of 28%.Vikas spent 1680 RS on its repairs and sold the motorcycle to Abhimanyu for 35910 RS, there by making a profit of 12.5%. Find the cost price of the motorcycle for Gaurav?

Answer:

The cost price of the motorcycle for Gaurav = RS.42000

We have to find:

The cost price of the motorcycle for Gaurav

Given that:

→Gaurav sold his motorcycle to Vikas at a loss 28%

→Vikas spent RS.1680 on its repairs and sold the motorcycle to Abhimanyu for RS.35910, there by making a profit of 12.5%

Step-by-step explanation:

Let, C.P of bikes = RS. x

⇒Gaurav sold the bike at y = x-28x/100=72x/100

C.P for Vikas=72x/100-1680

Profit=S.P-C.P/C.P×100

⇒125/100=S.P/C.P-1

⇒12.5/100=35910/C.P

⇒C.P=31920

⇒72x/100=30240

⇒x=RS.42000

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Therefore, the cost of the motorcycle for Gaurav is "RS.42000"