Question

Gaurav spent 1/3 of his pocket money on books and 3/4 of the remaining on chocolates. If he spent a total of Rs. 62.50, how much money did he have at first ?

Answer 1

Let $x$ be the total money, Gaurav had in the beginning.

As per question, he spent $\dfrac{1}{3}rd$ on books i.e. $\dfrac{x}{3}$.

Remaining amount = $x - \dfrac{x}{3}$ = $\dfrac{2x}{3}$.

Now, $\dfrac{3}{4}th$ of the remaining $\dfrac{2x}{3}$ spent on chocolates i.e.

$\dfrac{3}{4} \times \dfrac{2x}{3}\\\Rightarrow \dfrac{x}{2}$

As per question, total money spent on books and chocolates is Rs. 62.50.

$\Rightarrow \dfrac{x}{3} + \dfrac{x}{2} = 62.50\\\Rightarrow \dfrac{5x}{6} = 62.50\\\Rightarrow x = 75$

Hence, Gaurav had Rs. 75 at first.

Answer 2

Answer:

answer is x= 75

Step-by-step explanation:

let X be the initial amount of money that Gaurav had

amount spend on books is equal to 1/3x

remaining money after buying the books = x - 1/3x = 3x-x/3

amount spent on chocolate = 3/4 X 2/3x = x/2

given that he is spend a total of rupees 62.50

x/3 + x/2 = 62.50

multiply both side of the equation by 6 ( LCM of 2 and 3 is 6)

6x/3 + 6x/2=6 X 62.50

2x + 3x = 375

5x = 375

x = 75