Question

Gaurav takes 15 rounds of a rectangular park whose length is twice its breadth. If total distance covered by Gaurav is 900 m, find the length and breadth of the park.​

Answer 1

Answer :-

• Length of rectangular park = 20 m
• Breadth of rectangular park = 10 m

Given :-

• Total Rounds covered by Gaurav = 15
• Total Distance covered by Gaurav = 900 m
• The Length is twice the rectangle breadth.

To Find :-

• Length and Breadth of rectangular park

Explanation :-

Let the Breadth to be 'x' m and then Length will be '2x' m

From the given data Gaurav completes 15 rounds of rectangular park and the perimeter of rectangle will be 1 round that is covered by Gaurav.

$\rm \implies Perimeter \; of \; Rectangular \; Park = \dfrac{900}{15} \; m \\ \\ \\ \underline { \boxed { \rm \implies \bold { Perimeter \; of \; Rectangular \; Park = 60 \; m }}}$

Now, we know

$\rm \implies \text {Perimeter of Rectangle = 2(L + B) } \\ \\ \rm \implies \text { 2(L + B) = 60 m }} \\ \\ \rm \implies \text { 2(2x + x) = 60 m }} \\ \\ \rm \implies \text { 3x = } \dfrac{60}{2} \; m }} \\ \\ \rm \implies \text { 3x = 30 m } \\ \\ \rm \implies \text { x = } \dfrac{30}{3} \; m } \\ \\ \rm \underline { \boxed { \implies \bold {x = 10 \; m }}}$

Now, Substituting the values

$\rm \odot \; Lenght = 2x = 2(10) } = \bold { 20 \; m } \\ \\ \rm \odot \; Breadth = x = 1(10) } = \bold { 10 \; m }$

Hence, the Length and Breadth are 20 cm and 10 cm respectively.

@Agamsain

Answer 2

Answer:

Step-by-step explanation:

length :2x meters

breadth :x meters

perimeters of a rectangular park= 900/15 =60 meters

perimeters =2 ( l + b )

2( l + b ) = 60 meters

2 ( 2x + x ) = 60 meters

3x=60/2 meters

3x = 30 meters

x = 10 meters

length = 2x = 2(10) = 20 meters

breadth = x = 1(10) = 10 meters .