Gauss law in electrostatics is true for any closed surface ,no matter wat its shape or size is.justify this statement with an example
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Flux depends on the charge enclosed by the surface only that’s why there will be no effect of the area of any closed surface.
Formula is
Flux=Charge/ primitively of vacuum
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Gauss's Law :
The total electric flux over a closed surface in vacuum is equal to 1/ε₀ the total charge enclosed by the surface.
if q is the charge enclosed by surface S, The total electric flux through the surface S is Φ=q/ε₀
while measuring the electric flux, surface area is more important than its volume or its size.
Example:
let us consider a closed surface S encloses a point charges +q1,-q2,+q3 and -q4, the total charge enclosed is q= q1-q2+q3-q4
∴electric flux across S will be Φ=q/ε₀=(q1-q2+q3-q4)/ε₀
The total electric flux is zero if no charge is enclosed by the surface.
conclusion:
The closed surface chosen for application of Gauss's law is called as Gaussian surface. It can be of any shape or size.
The total electric flux over a closed surface in vacuum is equal to 1/ε₀ the total charge enclosed by the surface.
if q is the charge enclosed by surface S, The total electric flux through the surface S is Φ=q/ε₀
while measuring the electric flux, surface area is more important than its volume or its size.
Example:
let us consider a closed surface S encloses a point charges +q1,-q2,+q3 and -q4, the total charge enclosed is q= q1-q2+q3-q4
∴electric flux across S will be Φ=q/ε₀=(q1-q2+q3-q4)/ε₀
The total electric flux is zero if no charge is enclosed by the surface.
conclusion:
The closed surface chosen for application of Gauss's law is called as Gaussian surface. It can be of any shape or size.
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