Gauss law in electrostatics is true for any closed surface ,no matter wat its shape or size is.justify this statement with an example
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Answered by
89
Gauss's Law :
The total electric flux over a closed surface in vacuum is equal to 1/ε₀ the total charge enclosed by the surface.
if q is the charge enclosed by surface S, The total electric flux through the surface S is Φ=q/ε₀
while measuring the electric flux, surface area is more important than its volume or its size.
Example:
let us consider a closed surface S encloses a point charges +q1,-q2,+q3 and -q4, the total charge enclosed is q= q1-q2+q3-q4
∴electric flux across S will be Φ=q/ε₀=(q1-q2+q3-q4)/ε₀
The total electric flux is zero if no charge is enclosed by the surface.
conclusion:
The closed surface chosen for application of Gauss's law is called as Gaussian surface. It can be of any shape or size.
The total electric flux over a closed surface in vacuum is equal to 1/ε₀ the total charge enclosed by the surface.
if q is the charge enclosed by surface S, The total electric flux through the surface S is Φ=q/ε₀
while measuring the electric flux, surface area is more important than its volume or its size.
Example:
let us consider a closed surface S encloses a point charges +q1,-q2,+q3 and -q4, the total charge enclosed is q= q1-q2+q3-q4
∴electric flux across S will be Φ=q/ε₀=(q1-q2+q3-q4)/ε₀
The total electric flux is zero if no charge is enclosed by the surface.
conclusion:
The closed surface chosen for application of Gauss's law is called as Gaussian surface. It can be of any shape or size.
Answered by
20
Yeah its true..We have taken Gaussian surface in many cases spherical or cylindrical just because the equation becomes easy to solve...but u can take any type of surface any shape but the equation you will get will be a mess and difficultto solve
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