Physics, asked by Nickyijoshi6428, 1 year ago

Gauss law in electrostatics is true for any closed surface,no matter what its shape or size is,justify

Answers

Answered by kushalankur09p5h135
3
Gauss's Law :The total electric  flux over a closed surface in vacuum is equal to 1/ε₀ the total charge enclosed by the surface.if q is the charge enclosed by surface S, The total electric flux through the surface S is Φ=q/ε₀while measuring the electric flux, surface area is more important than its volume or  its size.Example: let us consider a closed surface S encloses a point charges +q1,-q2,+q3 and -q4, the total charge enclosed is q= q1-q2+q3-q4∴electric flux across S will be Φ=q/ε₀=(q1-q2+q3-q4)/ε₀The total electric flux is zero if no charge is enclosed by the surface.conclusion:The closed surface chosen for application of Gauss's law is called as Gaussian surface. It can be of any shape or size.
Answered by ramshyam7god
1
Total flux through surface is q/apsel not and hence there is no matter that either q is enclosed in a square or triangle or sphere and hence,guass law depends on charge enclosed in a closed surface not on the shape and size of a surface.....
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