gauss theroem explain with a example
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What Is Gauss' Law?
Gauss' Law is a law that describes what an electric field will look like due to a known distribution of electric charge. It was first formulated in the 19th century. Gauss' Law also comprises one of the four Maxwell's Equations that describe the force of electromagnetism.
To be more specific, Gauss' Law can be explained in words as: the total of the electric flux out of a closed surface is equal to the magnitude of the charge enclosed divided by the permittivity of free space. As a mathematical equation, it looks like this:
Examples
This might be easier if we went through a few examples. Let's first go back to the sphere.
Gauss' law tells us that the flux is equal to the charge Q, over the permittivity of free space, epsilon-zero. But flux is also equal to the electric field E multiplied by the area of the surface A. So EA equals Q over epsilon-zero.
For a sphere, the surface area is given by 4pir^2, so we can plug that in for A. And finally, if we rearrange for the electric fieldE, we find that the electric field Es is equal toQ over 4piepsilon-zeror^2. This is an expression for the electric field created by a charged sphere.
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Gauss' Law is a law that describes what an electric field will look like due to a known distribution of electric charge. It was first formulated in the 19th century. Gauss' Law also comprises one of the four Maxwell's Equations that describe the force of electromagnetism.
To be more specific, Gauss' Law can be explained in words as: the total of the electric flux out of a closed surface is equal to the magnitude of the charge enclosed divided by the permittivity of free space. As a mathematical equation, it looks like this:
Examples
This might be easier if we went through a few examples. Let's first go back to the sphere.
Gauss' law tells us that the flux is equal to the charge Q, over the permittivity of free space, epsilon-zero. But flux is also equal to the electric field E multiplied by the area of the surface A. So EA equals Q over epsilon-zero.
For a sphere, the surface area is given by 4pir^2, so we can plug that in for A. And finally, if we rearrange for the electric fieldE, we find that the electric field Es is equal toQ over 4piepsilon-zeror^2. This is an expression for the electric field created by a charged sphere.
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