Question

Gave me answer of these 2 question please tell fast

Answer 1

1) An isosceles right triangle has an equal base and height

so, height = base
let base and height be x

its area is 8 cm²

so, area of triangle = 1/2(base * height)
8 = (x*x)/2
x² = 16
x = 4

so base of triangle is 4cm and height of triangle is 4cm

2)The area of the larger circle = 100cm²

so, area of circle = πr²
$100 = \pi \times {r}^{2} \\ 100 = \frac{22}{7} \times {r}^{2} \\ {r}^{2} = 100 \times \frac{7}{22} \\ r = \sqrt{100 \times \frac{7}{22} } \\ r = 10 \sqrt{ \frac{7}{22} } (or) \: 10 \sqrt{0.31818}$
thus area of smaller circle not need for this calculation

so radius of larger circle = 10√(0.31818) cm