Question

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Answer 1

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Answer 2

Answer:

Here,

$theta \: = x \\ { \tan}^{2} x - \frac{1}{ { \cos }^{2} x} \\ = \frac{ { \sin}^{2} x}{ { \cos}^{2} x} - \frac{1}{ { \cos}^{2} x} \\ = \frac{ { \sin }^{2} x - 1}{ { \cos}^{2}x } \\ = - \frac{ { \cos}^{2} x}{ { \cos }^{2}x } \\ = - 1$

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