Gayatri was making a mathematical model, in which she placed 4 cubes each of edge 20cm one above another. find the surface area of the resulting cuboid
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Answered by
32
total cube that gayatri was placed=4
side of cube=20cm
Total surface area of cube 6a^2
T. S. A. =6*20^2
=6*400
=2400cm^2
T. S. A. of 1 cube=2400cm^2
T. S. A. of 4 cubes=2400*4=9600cm^2
surface area of resulting cuboid =9600cm^2
side of cube=20cm
Total surface area of cube 6a^2
T. S. A. =6*20^2
=6*400
=2400cm^2
T. S. A. of 1 cube=2400cm^2
T. S. A. of 4 cubes=2400*4=9600cm^2
surface area of resulting cuboid =9600cm^2
Answered by
19
Answer:
7200 cm^2
Step-by-step explanation:
side of cube=20cm
In the cuboid formed,
length =20+20+20+20 = 80cm
its height=breadth=20cm
T.S.A of cuboid=2 (lb + bh +hl)
=2(80*20 + 20*20 + 80*20)
=2(1600 + 400 + 1600)
=2*3600
=7200 cm^2
TSA of the cubes cannot be added all together to find the TSA of cuboid due to the hidden sides when stacked together..
hope it helps..
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