Question

gcd of 1
8(x³-x²+x-1) adn 12(x⁴-1)
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Answer 1

Step-by-step explanation:

Step 1: List the prime factors of each of the given number. For algebraic expression we have to find factors of them.

Step 2: List the common factors of the given numbers or common factors.

Step 3: Multiply those common factors.

(5) Find the GCD of the following

2 x² - x - 1 , 4 x² + 8 x + 3

Solution:

2 x² - x - 1 = (2 x + 1) (x - 1)

4 x² + 8 x + 3 = (2x + 3) (2x + 1)

Therefore the greatest common divisor = (2 x + 1)