Question

Ge and Si diodes conduct at 0.3 V and 0.7 V
respectively. The value of Vo is
(1) 0.5 V
(2) 0.4 V
(3) 0.3 V
(4) 0 V​

Answer 1

Answer:

of vo

1)0.5 is the value

Answer 2

The value of $V_0$ is $0.4volt$

Explanation:

Given-

Ge diode conducts at 0.3 Volt

Si diode conducts at 0.7 volt

Without reversing the connection initial value of $V_0$ is

We can clearly see from the attached figure Initially Ge & Si  both diodes are forward biased so current will effectively pass through Ge diode with a drop of 0.3 V   because current will prefer less voltage diode i.e. Ge diode which is having 0.3 V

We know that-

                   $V_0 = IR$

By substituting the value we get

                   $V_0=(\frac{10-0.3}{9} )\multiplivation 9 = 9.07 Volt$

When diode connections are reversed then, Ge diode will not conduct current because Ge diode changes into reverse bias.

So current will flow through "Si" diode hence an effective drop of

                      $V_0 = IR$

                     $V_O = (\frac{ 10 - 0.7}{9}) \mul9= 9.3 volt$

Change in $V_O(\Delta V_0) = 9.7 - 9.3 = 0.4 Volt$

so the value of $V_0$ is $0.4volt$