Question

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In a triangle ABC, AB = 15cm, BC = 13cm and AC = 14cm
Find the area of triangle ABC and hence its altitude on AC.
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Answer 1

Answer:

Semi perimeter = 15+13+14/2

Semi perimeter = 15+13+14/2 = 42/2

Semi perimeter = 15+13+14/2 = 42/2 = 21

Semi perimeter = 15+13+14/2 = 42/2 = 21 So by herons formula = whole number

Semi perimeter = 15+13+14/2 = 42/2 = 21 So by herons formula = whole number root 21(21-15) (21-14) (21-13)

Semi perimeter = 15+13+14/2 = 42/2 = 21 So by herons formula = whole number root 21(21-15) (21-14) (21-13)= whole ubder root 21 (6)(7)(8)

Semi perimeter = 15+13+14/2 = 42/2 = 21 So by herons formula = whole number root 21(21-15) (21-14) (21-13)= whole ubder root 21 (6)(7)(8)whole number root 7056

Semi perimeter = 15+13+14/2 = 42/2 = 21 So by herons formula = whole number root 21(21-15) (21-14) (21-13)= whole ubder root 21 (6)(7)(8)whole number root 705684 m^2

Answer 2

Answer:

this can be solve by heron's formula I.e.

$\ \sqrt{} s(s - a)(s - b)(s - c)$

where s = semi perimeter

here, perimeter is 15cm +13cm+ 14cm=42cm

so perimeter will be 42/2=21

$\sqrt{21(6)(7)(8)}$

=√7056=84cm^2