Question

Geeta age is 3 times his son age ten years ago he is 5 times his son age find their present age
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Answer 1

Geeta = 50 Years

Son = 20 Years

Step-by-step explanation:

Given:

• Geeta age is 3 times his son age.
• Ten years ago she was 5 times of son age.

To Find:

• What is their present ages ?

Solution: Let the present age of son was x years. Therefore,

Present age of Geeta = 3 times of x

Geeta's age = 3x years

[ 10 years ago their ages were ]

• Son's age = (x – 10) years
• Geeta's age = (3x – 10) years

A/q

• Ten years ago she was 5 times of son age.

$\implies{\rm }$ (3x – 10) = 5(x – 10)

$\implies{\rm }$ 3x –10 = 5x – 50

$\implies{\rm }$ 3x – 5x = – 50 + 10

$\implies{\rm }$ – 2x = – 40

$\implies{\rm }$ 2x = 40

$\implies{\rm }$ x = 40/2

$\implies{\rm }$ x = 20

So, their present ages are

• Son's age is x = 20 years

• Geeta age is 3(20) – 10 = 60 – 10 = 50 years

Answer 2

Answer:

✡ Question ✡

☞ Geeta age is 3 times his son age ten years ago he is 5 times his son age find their present age.

✡ Given ✡

✏Geeta age is 3 times his son age.

✏Ten years ago she was 5 times of son age.

✡ To Find ✡

✏What is their present ages ?

✡ Solution ✡

✏ Let the present age of son was x years.

Now,

▶Present age of Geeta=3 times of x

▶Geeta's age = 3x years

➡[ 10 years ago their ages were ]

▶Son's age = (x – 10) years.

▶Geeta's age = (3x – 10) years.

⭐ According to the question,

▶Ten years ago she was 5 times of son age.

=> (3x – 10) = 5(x – 10)

=> 3x –10 = 5x – 50

=> 3x – 5x = – 50 + 10

=> – 2x = – 40

=> 2x = 40

=> x = 40/2

=> x = 20

➡So, their present ages are;

☞Son's age is x = 20 years

☞ Geeta age is 3(20) – 10 = 60 – 10 = 50 years

Step-by-step explanation:

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