Math, asked by sreeya1126, 7 months ago

Geeta borrowed Rs.50000 from state bank of India at 11% p.a compound interest. At the end of one year she repaid Rs.3500 and Rs.27720 at the end of the second year. Find the amount outstanding at the beginning of the third year.

Answers

Answered by sulagnapalit8263
9

Principle = Rs.50000

rate of interest,r = 11%

After 1 year, interest

 =\frac{50000 \times 11 \times 1}{100}

 = 5500

After 1 year, total

 =  50000 + 5500 = 55500

At the end of one year she repaid Rs.3500.

Total outstanding after 2 year

 = 55500 - 3500 = 52000

After 2 year, interest

 =  \frac{52000 \times 11}{100}  = 5720

Total= 52000-5720=46280

Outstanding at the beginning of the third year

= 46280-27720

=18560

Hence,the amount outstanding at the beginning of the third year is 18560.(Ans)

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