Question

Geeta had 30 problems for homework she worked out two by three of them how many problems was still left to be worked out by her.
Please show me the full sum.​

Answer 1

Answer :-

$\bf\huge\boxed{10}$

Explanation :-

Given :

• Total number of problems for homework Geeta had - 30
• Fraction of problems done by Geeta - 2/3

To find :

The number of problems still left to be worked out by Geeta

Solution :

Number of problems done by Geeta :-

$= \dfrac{2}{3} \: of \: 30$

$= \dfrac{2}{3} \times 30$

$= 2 \times 10$

$= 20$

Therefore, Remaining problems :-

= (Total number of problems - Number of problems done by Geeta)

= (30 - 20)

= 10

Hence, the problems still left to be worked out by Geeta are 10 respectively.

Answer 2

$\mathfrak{\large{\underline{\underline{Answer:-}}}}$

Geeta was left with 10 sums to be solved.

$\mathfrak{\large{\underline{\underline{Explanation:-}}}}$

Given :

Number of Problems Geeta had = 30

She was able to solve $\dfrac{2}{3}$ of 30

To Find :

Problems left to solve with Geeta

Solution :

As Geeta was able to solve $\dfrac{2}{3}$ of the total sums, find the Number of sums she solved.

$\sf{\longrightarrow} \: \dfrac{2}{3} \: of \: 30$

$\sf{\longrightarrow} \: \dfrac{2}{3} \times 30$

$\sf{\longrightarrow} \: 2 \times 10$

$\sf{\longrightarrow} \: 20$

Geeta was able to solve 20 sums out of the 30.

$\rule{300}{1.5}$

Sums Geeta couldn't solve =

Subtract the number of sums solved from the total number of sums.

• Sums solved = 20
• Total = 30

$\sf{\longrightarrow} \: 30 - 20$

$\sf{\longrightarrow} \: 10$

$\therefore$ Geeta was left with 10 sums to be solved.