Question

Geeta has a piece of land which is in the shape of rhombus. She wants her daughter and son to work on the land and grow different crops. She divided the land into 2 equal parts. If the perimeter of the land is 400m and one of the diagonal is 160m. How much area each of them will get for their crops?​

Answer 1

Answer:

4800

Step-by-step explanation:

Let ABCD be the field. Given perimeter = 400 m

So, each side = 400/4 = 100 m

Diagonal BD = 160 m

Let a = 100 m, b = 100 m, c = 160 m

∴ s = (a + b + c)/2  = (100 + 100 + 160)/2 = 180 m.

Therefore,   Area of △ABD = root under (√s(s - a)(s - b)(s - c))

 = root under (√180(180 - 100)(180 - 100)(180 - 160))

 = root under (√180 x 80 x 80 x 20) = 4800 m2