Geeta moves along the boundary of a square field of side 20m in 80s. What will be the magnitude of displacement at the end of 200s? Also calculate the average velocity
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Step-by-step explanation:
in 80s geeta can cover 20m.which means in 200 sec she can cover 80(x)=20×200.
80x=4000
x=500m.
Avg velocity(v)=total distance/total time
=500+20/200+80
=520/280
=2
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