Question

Geeta moves along the boundary of a square field of side 20m in 80s. What will be the magnitude of displacement at the end of 200s? Also calculate the average velocity​

Answer 1

Answer:

perimeter of the field =4×20m=80m(in 80 secs)

. ' .she covers 200m in 200 secs

. ' .displacement after 200 secs=diagonal of the square=20m

avg velocity=total displacement/total time

=20/200=0.1m/s