Math, asked by uditparekh, 7 months ago

gelo
. I and m are two parallel lines intersected by
another pair of parallel lines p and q
(see Fig. 7.19). Show that A ABC=ACDA.
р
g
А
D
m
В B.
C​

Answers

Answered by kripajohn
1

Answer:

gelo or hello?????

and where is the fig

Answered by CommanderBrainly
3

Step-by-step explanation:

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Solution:

It is given that p q and l m

To prove:

Triangles ABC and CDA are similar i.e. ΔABC ΔCDA

Proof:

Consider the ΔABC and ΔCDA,

(i) BCA = DAC and BAC = DCA Since they are alternate interior angles

(ii) AC = CA as it is the common arm

So, by ASA congruency criterion, triangle ABC triangle CDA.

 \huge\large\bf{\underline\green{❥thαnk \; чσu ♥♥}}

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