Math, asked by Azazelsatan, 2 months ago

general solution for sin 20+ sin 40+ sin 60 = 0​

Answers

Answered by xXSTANGERXx
3

Answer:

Consider LHS

sin 20 × sin 40 × sin60 × sin80

Sin Values

sin 0° = √(0/4) = 0

sin 30° = √(1/4) = ½

sin 45° = √(2/4) = 1/√2

sin 60° = √3/4 = √3/2

sin 90° = √(4/4) = 1

LHS = sin60 [sin20 × sin40 × sin80]

LHS = √3/2[sin20 × sin(60 – 20) × sin(60 + 20)]

LHS = √3/2[sin 3(20)/4]

LHS = √3/2[sin 60/4]

LHS = √3/2[√3/2 × 4]

LHS = √3/2 × √3/8

LHS = 3/16

∴ LHS = RHS

Step-by-step explanation:

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