General solution of 2cos²x +3 sin x = 0
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Hi Friend !!!
Here is ur answer !!!
2(1-sin²x) + 3sinx = 0
2 - 2sin²x + 3sinx = 0
2sin²x - 3sinx - 2 = 0
2sin²x - 4sinx + sinx -2 = 0
2sinx(sinx-2) +1(sinx-2) = 0
sin x = -1/2 or 2
General solutions are 2nπ-π/6
Hope it helps u
:-)
Here is ur answer !!!
2(1-sin²x) + 3sinx = 0
2 - 2sin²x + 3sinx = 0
2sin²x - 3sinx - 2 = 0
2sin²x - 4sinx + sinx -2 = 0
2sinx(sinx-2) +1(sinx-2) = 0
sin x = -1/2 or 2
General solutions are 2nπ-π/6
Hope it helps u
:-)
mntrjhnpdyzdd:
thank U friend
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