Question

General solution of sin20 =0
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Answer 1

Answer:

Step-by-step explanation:

1. If sin θ = 0 then θ = nπ, where n = zero or any integer.

2. If sin θ = sin ∝ then θ = nπ + (-1)n ∝, where n = zero or any integer.

3. If sin θ = 1 then θ = (4n + 1)π2, where n = zero or any integer.

4. If sin θ = -1 then θ = (4n - 1)π2, where n = zero or any integer.

5. If cos θ = 0 then θ = (2n + 1)π2, where n = zero or any integer.

6. If cos θ = cos ∝ then θ = 2nπ ± ∝, where n = zero or any integer.