general solution of sin2x = 0
Answers
Answered by
0
Answer:
this is your answer
Step-by-step explanation:
⇒ θ = nπ2, where, n = 0, ± 1, ± 2, ± 3,……. Therefore, the general solution of the equation sin 2θ = 0 is θ = nπ2, where, n = 0, ± 1, ± 2, ± 3
mark me as brainliest please mate
Similar questions