Question

general solution of tanø+tan2ø+√3tanøtan2ø=√3​

Answer 1

really very hard

don't know

Answer 2

Answer:

ø=nπ/3 ± π/9

Step-by-step explanation:

tanø + tan2ø = √3(1 - tanøtan2ø)

(tanø + tan2ø)/1 - tanøtan2ø =√3

tan3ø = √3

3ø = nπ ± π/3

ø = nπ/3 ± π/9