Question

Generate the following pattern :
1) 10 20 30 40 50 2) 5
10 20 30 40 5 10
10 20 30 5 10 15
10 20 5 10 15 20
10 5 10 15 20
25

3) 1 3 5 7 9
3 5 7 9
5 7 9
7 9
9

4) #
# #
# # #
# # # #

Answer 1

Explanation:

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\text{\huge\underline{\red{Question:-}}}

Question:-

:\Longrightarrow⟹ The breaks applied to a car produce an acceleration of 6m/s 2 in the opposite direction to the motion. If the car takes 2s to stop after the application of breaks , calculate the distance it travels during this time?

\text{\huge\underline{\orange{Given:-}}}

Given:-

:\Longrightarrow⟹ Acceleration , a = -6m/s².

:\Longrightarrow⟹ Time , t = 2s.

:\Longrightarrow⟹ Final velocity, v = 0m/s.

\text{\huge\underline{\green{To\ find:-}}}

To find:-

:\Longrightarrow⟹ If the car takes 2s to stop after the application of breaks , calculate the distance it travels during this time

\text{\large\underline{\blue{By\ using\ formula:-}}}

By using formula:-

:\Longrightarrow⟹ 1. v = u + at.

:\Longrightarrow⟹ 2. s = u + \mathrm{\dfrac{1}{2}}

2

1

at².

\text{\huge\underline{\purple{Solution:-}}}

Solution:-

:\Longrightarrow⟹ v = u + at

:\Longrightarrow⟹ 0 = u - 6 × 2

:\Longrightarrow⟹ u = 12m/s.

:\Longrightarrow⟹ s = u + \mathrm{\dfrac{1}{2}}

2

1

at²

:\Longrightarrow⟹ s = 12 × 2 + \mathrm{\dfrac{1}{2}}

2

1

× (-6) × 4

:\Longrightarrow⟹ s = 12m.

\text{\huge\underline{\bf{Hence,\ Verified}}}

Hence, Verified