Question

♧Genius
♧Maths Aryabhatta
♧Ace
♧Brainly Moderator


A ladder of length 10 m resting on wall of height 8 m slips down such that it stop at a height 6 m from the ground. Then, find the distance of the new position of foot of the ladder from the base of the wall and from the original position of the foot of ladder.

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Answer 1

Answer: x=6

Step-by-step explanation:

it is 6 meters away

bcoz the ladder and ground are perpendicular to each other

so then the height and distance from base are adjacent and opposite sides and the ladder is 10 meter

so let's apply Pythagoras theorem

therefore 10^2 = 8^2 +x^2

100 = 64 + x^2

100-64 = x^2

36 = x^2

6^2 = x^2

therefore x = 6

the distance from base is 6 meter away

hope u understand this

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Answer 2

8m

let the distance between them be xm

Length of wall 8m,after slipping it becomes 6m

hypotenuse is 10 m

x^= 10^-6^

x^= 100-36

x^= 64

x = √64

x = 4

distance between them is 4m