Geometrical verification of idmities (1.(a+b)=a squre+2ab+b squre.
2.(a-b) squre=a squre -2ab+b squre)
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1
(a+b)²=(a+b)(a+b)
=(a²+ab+ab+b²)
=a²+2ab+b²
(a-b)²=(a-b)(a-b )
=(a²+b²-ab-ab)
=a²-2ab+b²
=(a²+ab+ab+b²)
=a²+2ab+b²
(a-b)²=(a-b)(a-b )
=(a²+b²-ab-ab)
=a²-2ab+b²
Answered by
2
just expand the identities
(a+b)^2 can be written as (a+b)(a+b)
according to the rule of polynomial multiplication
a(a+b)+b(a+b)
=a^2+ab+b^2+ab
hence proved
similarly
(a-b)^2=(a-b)(a-b)
so,a(a-b)-b(a-b)
a^2-ab -ba+b^2
that gives the second identity
(a+b)^2 can be written as (a+b)(a+b)
according to the rule of polynomial multiplication
a(a+b)+b(a+b)
=a^2+ab+b^2+ab
hence proved
similarly
(a-b)^2=(a-b)(a-b)
so,a(a-b)-b(a-b)
a^2-ab -ba+b^2
that gives the second identity
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