Question

geometry experts..... Find angle bcd

Answer 1

Hi,
Here is the answer to your query:-

$\texttt{Given-}$
ABCD is a cyclic quadrilateral.
angleDBC=55°, angleBAC=45°

$\texttt{To Find-}$
angleBCD.

$\texttt{Proof-}$
angleBAC=angleBDC
[Angles in the same segment]

angleBDC=45°

Now,
In ΔBDC, By angle sum property of triangles
angleBDC+angleDBC+angleBCD=180°
45°+55°+angleDBC=180°
100°+angleDBC=180°
angleDBC=180°-100°
angleDBC=80°.

Your answer is 80°

$\textsf{THANKS}$